CS604 Idea Solution

by plhr60 Fri Nov 04, 2011 11:56 am

for q=2
take an idea........

Code:: #include <stdio.h> /* printf, stderr, fprintf */ #include <sys/types.h> /* pid_t */ #include <unistd.h> /* _exit, fork */ #include <stdlib.h> /* exit */ #include <errno.h> /* errno */ int main(void) { pid_t pid; /* Output from both the child and the parent process * will be written to the standard output, * as they both run at the same time. */ pid = fork(); if (pid == -1) { /* Error: * When fork() returns -1, an error happened * (for example, number of processes reached the limit). */ fprintf(stderr, "can't fork, error %d\n", errno); exit(EXIT_FAILURE); } if (pid == 0) { /* Child process: * When fork() returns 0, we are in * the child process. * Here we count up to ten, one each second. */ int j; for (j = 0; j < 10; j++) { printf("child: %d\n", j); sleep(1); } _exit(0); /* Note that we do not use exit() */ } else { /* Parent process: * When fork() returns a positive number, we are in the parent process * (the fork return value is the PID of the newly created child process). * Again we count up to ten. */ int i; for (i = 0; i < 10; i++) { printf("parent: %d\n", i); sleep(1); } exit(0); } return 0; }